Circle basics
You must be able to recognise when an equation represents a circle.
Any equation of the form

will represent a circle, provided at least one of
p,
q and
r is not zero.
The
general equation of a circle normally appears in the form

where
(-g, -f) is the centre of the circle and

is the radius.
Notice that for the circle to exist

.
Look at the following worked examples.
For

so equation represents a circle with centre =
(-3, 4) and radius

For

so

does not represent a circle.
For

we must write this starting

like this:

so equation represents a circle with centre =

and radius