Circle basics

Circle basics

You must be able to recognise when an equation represents a circle.

Any equation of the form x^2  + y^2  + px + qy - r = 0 will represent a circle, provided at least one of p, q and r is not zero.

The general equation of a circle normally appears in the form x^2  + y^2  + 2gx + 2fy + c = 0 where (-g, -f) is the centre of the circle and \sqrt {g^2  + f^2  - c} is the radius.

Notice that for the circle to exist g^2  + f^2  - c  0.

Look at the following worked examples.

For x^2  + y^2  + 6x - 8y - 11 = 0

g^2  + f^2  - c = (3)^2  + (-4)^2  - ( - 11) = 36

so equation represents a circle with centre = (-3, 4) and radius = \sqrt {36}  = 6

For x^2  + y^2  - 2x + 4y + 11 = 0

g^2  + f^2  - c = (-1)^2  + 2^2  - 11 =  - 6

so x^2  + y^2  - 2x + 4y - 11 = 0 does not represent a circle.

For 3x^2  + 3y^2  - 6x + y - 9 = 0 we must write this starting x^2  + y^2 like this:

\eqalign{     x^2  + y^2  - 2x + {1 \over 3}y - 3  =  0\cr\cr   g^2  + f^2  - c  =  ( - 1)^2  + ({1 \over 6})^2  - ( - 3) = 4{1 \over {36}} = {{145} \over {36}}\cr

so equation represents a circle with centre = (1, - {1 \over 6}) and radius \sqrt {{{145} \over {36}}}  = {{\sqrt {145} } \over 6}

DASAVATARAM

DASAVATARAM